Compability for parsing FRR like Quagga

master
Sebastian Lohff 7 years ago
parent 2af6d82058
commit 27923c756d

@ -256,6 +256,9 @@ def _quaggaFindNeighbors(info):
neighborDict = OrderedDict()
for raw in rawNeighbors:
descrIdx = 1 if raw[1][0] == "Description:" else 0
if raw[descrIdx + 1][0] == "Hostname:":
descrIdx += 1
peerdict = {
"neighbor_address": raw[0][3].rstrip(","),
"neighbor_as": int(raw[0][6].rstrip(",")),
@ -321,7 +324,7 @@ def _quaggaFindRoutes(raw):
foundTable = True
else:
if line != '':
if line.startswith("Total number of prefixes"):
if line.startswith("Total number of prefixes") or line.startswith("Displayed "):
break
else:
# parse one route line

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